The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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Not sure right now give me a few mins
You do
-26
-4
---
-30
5n=-30 so...
-30/5=-6
Therefore
n=-6
Hey there!
-4.36 + 1.2 [2.8 +(-3.51)]
= -4.36 + 1.2(2.8 - 3.51)
= 4.36 1.2(-0.71)
= -4.36 - 0.852
= -5.212
Therefore, your answer is: -5.212
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.
<h3>What is the union of events J and K?</h3>
It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.
<h3>What is the complement?</h3>
The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:
15 + x = 58
x = 43.
The number of outcomes that are possible for the complement of the union of Events J and K is of 43.
More can be learned about complementary events at brainly.com/question/9752956
