Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
given
p=q^3
p=40
______
q=(p)^1/3
q=(40)^1/3-->q=2(5)^1/3
Now
the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.
finally the value of p gonna be
p=q^3
p=(5^1/3) ^ 3
p=5
Hello.
The answer is
-12y
Combine Like Terms:<span>=<span><span><span>6y</span>+<span>−<span>6y</span></span></span>+<span>−<span>12y</span></span></span></span><span>=<span>(<span><span><span>6y</span>+<span>−<span>6y</span></span></span>+<span>−<span>12y</span></span></span>)</span></span><span>=<span>−<span>12<span>y
Have a nice day</span></span></span></span>
Look at the graph thoroughly .
It passes through origin and given some points
(-1,1)
(1,-1)
(2,-2)
(-2,2)
We observe that

Hence whatever the function be the result will be -x
Option D is correct