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2 years ago

There are 60 marbles in a bowl. 1/3 of them is red, 1/4 is blue and the rest has now colour. How many marbles have no colour?

Mathematics

2 answers:

Gwar [14]2 years ago

3 0

Answer:25

Step-by-step explanation: since 1/3 of the marbles is red, we’ll divide 60 by 3, which equals 20. Since 1/4th are blue, we’ll do 60/4=15. 20+15=35. We’re finding the amount with no color, so subtract 35 from 60. We have 25

Orlov [11]2 years ago

3 0

Answer:

25 marbles have no colour

STEP BY STEP EXPLANATION:

Marbles that are red =
$\frac{1}{3} \times 60 = 20$
Marbles that are blue =
$\frac{1}{4} \times 60 = 15$
Remaining marbles =
$60 - 20 - 15 = 25$

Therefore 25 marbles have no colour

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Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$