HELP ASAP I WILL MARK BRAINLEST

jeyben [28]

11. 8 * 18 = 144 in³, Option D

12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D

13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C

14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B

15. $\frac{10}{16} = \frac{x}{18}$ >> 16x = 180 >> x = 11.25 so Option B

16. Option D, 10 cm.

17. Option C, 8.5 in

18. Option B. 10.2 km

19. Option D. 0.82

20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C.

6 0

3 years ago

Para cambiar 212% a fracción debemos dividirlo entre 100% ?

kirza4 [7]

Si tiene que divide 212/100=53/25

4 0

3 years ago

HELP ASAP PLZ

WARRIOR [948]

You can use the formula to solve for the y-values in the table. Insert the x-value into the equation: y = 2x - 2

(ex. y = 2(1)-2)

So..

x | y

0 | -2

1 | 0

3 | 4

5 | 8

8 | 14

10 | 18

[First time answering on Brainly so I accidentally commented the answer instead. Don’t know how to delete the comment but anyways, I hope my response helped you!]

4 0

3 years ago

A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long

alexdok [17]

Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
$tan \alpha = \frac{C}{D}$
Similarly we can do for large triangle containing flagpole:
$tan \alpha = \frac{A}{B}$

We see that these two equations have same left sides. This means that their right sides must also be same:
$\frac{C}{D} = \frac{A}{B}$
We can solve for A:
$CB=AD \\ A= \frac{CB}{D} \\ A= \frac{6*24}{3} \\ A=48 ft$

Height of flagpole is 48 feet.

8 0

3 years ago

Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast

Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

__

b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

__

c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

__

d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

_____

If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

6 0

3 years ago