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shusha [124]
3 years ago
12

What is the value of X

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

9

Step-by-step explanation:

We have,

  • Angle GHI = (20x – 8)°
  • Angle QHI = (14x + 14)°
  • Angle GHQ = 32°

According to the question,

→ Angle GHQ + Angle QHI = Angle GHI

→ 32° + (14x + 14)° = (20x – 8)°

→ 32° + 14x° + 14° = 20x° – 8°

→ 46° + 14x° = 20x° – 8°

→ 46° + 8° = 20x° – 14x°

→ 54° = 6x°

→ 54° ÷ 6° = x

→ <u>9</u><u> </u><u>=</u><u> </u><u>x</u>

The value of x is 9.

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You have a puppy named Fido and 60 feet of fencing. You want to make him the largest play area possible. What are the dimensions
LUCKY_DIMON [66]

Answer:

<u>15 feet x 15 feet</u>

Step-by-step explanation:

I'm worried about Fido, so I'll use three different approaches to maximizing his play space:  Graphing, Chart, and First Derivative.  This is perhaps more than Fido wants, but it hopefully offers ideas on how these types of problems can be answered.

=========================

Fido is limited to 60 feet of fence, which will form the perimeter.  The area  of a rectangle is (length)*(width).  Let's set length to L and width to W.  I'll use A for area.

Therefore A = L*W

The rectangle's perimeter will be 2L + 2W, and this is equal to 60 feet:

2L + 2W = 60

Let's rearrange this equation to isolate either W or L.  I chose L:

L + W = 30

L = 30 - W

Now let's use this definition of L in the Area equation:

A = L*W

A = (30-W)*W

A = 30W - W^2

<u>Graphing</u>

We can graph this function (A = 30W - W^2) to find the maximum area.  See the attached image.  We find a maximum area of 225 ft^2 when the width is 15 feet.  15 feet would mean that Fido's roaming pen will be in the shape of a square;  15 feet for each side equals 60 feet total fence.

<u>Chart</u>

One can also find a maximum by calculating a variety of conditions set by L = 30 - W.  I randomly picked lengths from 2 to 24 feet and calculated the resulting width and then the resultant area for each condition.  See attached image.  Although I did not pick 15 feet, we can see that the area increases until the length transitions from 14 to 16 feet.  It reverses direction at that point. A closer inspection around those values will show that 15 feet is, in fact, the optimum value to produce a pen with the most area.

<u>First Derivative</u>

One could also take the first derivative of the equation A = 30W - W^2 and set it equal to zero.  The fist derivative tells us the slope of the line at any point (for a value of W in this example).  The slope is zero only when the curve hits a maximum.

A = 30W - W^2

A' = 30 -2W

0 = 30 - 2W

2W = 30

W = 15 feet

The slope is zero when the width is 15 feet.  15 feet is the optimum for creating a pen with the most area possible with 60 feet of fence.

===

All three approaches yield the same result.  Graphing is fun when you have access to DESMOS.  Charts are fun if you like Excel.  Derivatives can also be fun, mostly because I always ponder "Who had the audacity to think this might work?"  (Didn't they have something more important to do?  Raid a village, etc.?).

====

Arf

8 0
3 years ago
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Answer:

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Step-by-step explanation:

the answer in the picture

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I think that is proportional

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