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GREYUIT [131]
3 years ago
5

Simplify the expression below as much as possible.

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
The answer is 8+1 which is D
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What is (-6-4)divided by(-5)=
lbvjy [14]

= -2? i dont really know either

8 0
3 years ago
Read 2 more answers
In the table below, y varies inversely as x. What is the missing value?
Minchanka [31]

Answer:

<h2>The value of y is <u>0.5</u>, so the answer is <u>C</u>.</h2>

Step-by-step explanation:

Find first the constant of variation.

Given: x = 3, y = 4

Find: k = ?

Formula:

y =  \frac{k}{x}

Solution:

y =  \frac{k}{x}  \\ 4 =  \frac{k}{3}  \\ 12 = k

Then, find the value of y in the third box.

Given: x = 24, k = 12

Find: y = ?

Formula:

y =  \frac{k}{x}

Solution:

y =  \frac{k}{x}  \\ y =   \frac{12}{24} \\ y =  \frac{1}{2} \\\boxed{y = 0.5}

6 0
3 years ago
Neeeeed helpppppp please
MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = \frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}

                    = \frac{\text{Length of CD}}{\text{Length of GH}}

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

                       = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                       = \sqrt{(-7-0)^2+(0+7)^2}

                       = \sqrt{98}

                       = 7\sqrt{2}

Length of GH = Distance between G(0, -1) and H(-1, 0)

                       = \sqrt{(-1-0)^2+(0+1)^2}

                       = \sqrt{2}

Scale factor = \frac{7\sqrt{2} }{\sqrt{2} }

                    = 7

6 0
3 years ago
What is the greatest common factor you can use to divide the numerator and denominator of the fraction 28/32?
Anastaziya [24]
The greatest common factor is 4.

28/32 / 4 = 7/8
7 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
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