Area enclosed in
radians =$\pi r^2$
so area enclosed in $\theta$ radians=$\theta \times \frac{\pi r^2}{2\pi}= \frac{1}2\theta r^2$
does this answer your question?
So we are given two points, say P1(4,7), P2(x,19).
Slope is given by
m=3=(y2-y1)/(x2-x1)=(19-7)/(x-4)
solve for x
3=(19-7)/(x-4)
cross multiply
3(x-4)=12
3x-12=12
3x=12+12=24
x=8
Answer:
13/90 > 1/7 or 1/7 < 7/90
Step-by-step explanation:
to compare two rational expression you should make the denominator equal
1/7 ➡ ×90 = 90/630
13/90 ➡ ×7 = 91/630
I think the answer is 54 to question B but don't take my word for it.
Here's 9 - 13. If you need any further help, I'd gladly assist.