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solniwko [45]
3 years ago
9

Simplify 2/5(a+b)+3/5(a+c)

Mathematics
2 answers:
Evgen [1.6K]3 years ago
4 0

Distribute

(2/5) (a) + (2/5) (b) + (3/5)(a) +(3/5)(c)

= 2/5a+2/5b+3/5a+3/5c

Combine like terms

2/5 a + 2/5 b + 3/5 a + 3/5 c

= ( 2/5 a + 3/5 a ) + ( 2/5 b) +(3/5 c)

= a + 2/5 b +3/5 c


I hope that's help !

Sergeu [11.5K]3 years ago
3 0
Distribute 2/5 and 3/5 into the ():
2/5(a+b)+3/5(a+c)

2/5 a+ 2/5 b+3/5 a+ 3/5 c

combine the like terms:
2/5 a+3/5 a= 5/5 a --> 1a --> a

new simplified equation:
a+2/5 b+3/5 c
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Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

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(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

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