<span>when p = -24 and q = 4. p/2q= -24/8 = -3 </span>
Answer:
1) x = 8
2) ∠RPS = 36°
Step-by-step explanation:
<u>GIVEN :-</u>
- ∠QPS = 180°
- ∠QPR = 7x + 88
- ∠RPS = 3x + 12
<u>TO FIND :-</u>
- Value of x
- Measure of ∠RPS
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
In a straight line , if there are two angles such that their sum is equal to straight angle (or 180° in other words) , then those angles are known as linear pair.
<u>PROCEDURE :-</u>
1)
Measure of ∠QPS = 180° and it comprises of ∠QPR & ∠RPS.
⇒ ∠QPR & ∠RPS are linear pair.
⇒ ∠QPR + ∠RPS = 180°
⇒ 7x + 88 + 3x + 12 = 180°
⇒ 10x + 100 = 180
⇒ 10x = 180 - 100 = 80
⇒ x = 80/10 = 8
2)
x = 8. So,
∠RPS = 3×8 + 12 = 24 + 12 = 36°
Answer:
56
Step-by-step explanation:
To find the area of a rectangle we have the foruma A=WxL.
But we already have the area and length so we can plug that in
5488=Wx98
Now its an algebreic expression.
SInce its multiplying we do the opposite, so we divide 98 on both sides.
98/98 crosses itself out so now its 5488/98. Which equals 56. So now our expression is W=56. To fact check we put the numbers 56 and 98 into the formula to see if we get 5488.
A=56x98
A=5488
Area of the trapezoid = 1/2(B+b)h
where
B= length of the longer side of the trapezoid which is equal to 14 ft
b= shorter shorter side of the trapezoid which equal 8 ft
h = height of the trapezoid which is equal to 4 ft
Area of the trapezoid = 1/2 (14+8)4
Area of the trapezoid yard fence of Duc is 44ft^2
