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stepladder [879]
2 years ago
14

class A folds 160 fewer paper cranes than class B and 2/3 as many paper cranes as class C. Class B folds 92 more paper cranes th

an class C. How many paper cranes does class B fold?
Mathematics
1 answer:
krek1111 [17]2 years ago
3 0
Let x = Class A
Let y = Class B
Let z = Class C
Equations from problem:
x - 160 = y
2/3x = z
y + 92 = z
Solving through substitution:
2/3x = y + 92
2/3x = (x - 160) + 92
2/3x = x - 68
-1/3x = -68
3(-1/3x) = 3(-68)
-x = -204
x = 204
Now substitute x in the first equation to get y:
204 - 160 = y
44 = y
44 = Class B
There are 44  folded paper cranes in Class B.

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In ΔTUV, the measure of ∠V=90°, VT = 64 feet, and UV = 43 feet. Find the measure of ∠U to the nearest tenth of a degree.
lbvjy [14]

Answer:

47.8°

Step-by-step explanation:

Let's first outline the important parameters

--- <V = 90°

Vt = 64

UV = 43

The angles in a triangle sums up to 180,but we don't have up to 2 angles given so as to find the third one. What we have to is to find the second angle,in this case T,using the sine rule.

Sin v/v = sin t/t

(Sin 90)/64 = sin t/43

Cross multiply and we have

43 sin 90 = 64 sin t

Sin t = 43 sin 90 ÷ 64

Sin t = 0.6719

Sine inverse of t = 42.2°(the second angle)

Angle U = 180 -( 90 + 42.2)

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7 0
3 years ago
Read 2 more answers
2x + 3y = 5x - y complete the missing value in the solution to the equation
Leto [7]

Answer:

The missing value is(0,0)

Step-by-step explanation:

The complete question is:

2x+3y=5x-y

Complete the missing value in the solution to the equation.

( ,0)

<u>Solution:</u>

We have given:

2x + 3y = 5x - y

Combine the like terms:

2x-5x= -y-3y

-3x = -4y

Both negative signs will be cancelled out by each other.

So we have,

3x = 4y

We have given y = 0

Then

3x = 4*0

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Divide both sides by 3

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4 0
3 years ago
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Solve for x,y, and z.
Ann [662]

The given triangle is isosceles, so the two remaining angles in the triangle both have measure <em>xº</em>. The interior angles of any triangle sum to 180º, so that

58º + <em>xº</em> + <em>xº</em> = 180º

58 + 2<em>x</em> = 180

2<em>x</em> = 122

<em>x</em> = 61

Angles <em>y</em> and <em>z</em> are supplementary to angle <em>x</em>, so that

<em>xº</em> + <em>yº</em> = 180º

and

<em>xº</em> + <em>zº</em> = 180º

and consequently, <em>y</em> = <em>z</em>. In particular, we get

<em>y</em> = 180 - 61

<em>y</em> = 119

and so

<em>z</em> = 119

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