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Nata [24]
2 years ago
11

6n +5<7n + 10

Mathematics
1 answer:
RoseWind [281]2 years ago
8 0

Answer:

the answer is

Step-by-step explanation:

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Ill give you brainliest&gt;&gt;&gt;Write an equation of the line passing through the point (5, 2) that is perpendicular to the l
11Alexandr11 [23.1K]

y= mx+b

(16, -7) = (x,y)

2(16) - 3y = 12

32 - 3y = 12

32 - 12 = 3y

20/3 = y

6.6 = y

2x-3(-7) = 12

2x+21 = 12

2x = 12 - 21

x = -9/2

Insert the values into y = mx + b

solve for m and then solve for b

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3 years ago
I will mark brainliest
Novosadov [1.4K]

Answer: 48.54101966249685

Step-by-step explanation:

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3 years ago
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Please help me with these questions , thank you​
Angelina_Jolie [31]

Answer:

1. 4x^{3} + 26x² + 4x - 48

2. 2x^{3} - 23x² + 60x - 32

3. x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4. 2x^{7} + x^{6} - 28x^{5} + 3x + 12

Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

x(4x² + 2x - 8)  +  6(4x² + 2x - 8)

4x^{3} + 2x² -8x  +  6(4x² + 2x -8)

4x^{3} + 2x² -8x + 24x² + 12x - 48

Combine like terms:

4x^{3} + 26x² + 4x - 48

2) Distribute the parenthesis (x - 8):

x(2x² - 7x + 4)  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  -16x² + 56x - 32

Combine like terms:

2x^{3} - 23x² + 60x - 32

3) Distribute the parenthesis (x + 2):

x(x^{4} + 7x² - 4)  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

No like terms to combine, so:

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4) Distribute the parenthesis (x + 4):

x(2x^{6} - 7x^{5} + 3)  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x + 8  x^{6} - 28x^{5} + 12

Combine like terms:

2x^{7} + x^{6} - 28x^{5} + 3x + 12

hope this helps!

8 0
2 years ago
[IMPORTANT PLEASE READ!!] I am currently at home, I'm in summer school for Algebra 1. I'm taking a pre-test, once I finish this
Llana [10]
<h2>Answer:</h2>

The vertex of the function is:

                             (-2,-2)

<h2>Step-by-step explanation:</h2>

We are given a absolute value function f(x) in terms of variable "x" as:

                       f(x)=-|x+2|-2

We know that for any absolute function of the general form:

f(x)=a|x-h|+k

the vertex of the function is : (h,k)

and if a<0 the graph of function opens downwards.

and if a>0 the graph of the function opens upwards.

Hence, here after comparing  the equation with general form of the equation we see that:

a= -1<0 , h= -2 and k= -2

Since a is negative , hence, the graph opens down .

         Hence, the vertex of the function is:

                         (-2,-2)

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3 years ago
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Anna11 [10]

Answer:

-0.5

Step-by-step explanation:

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