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2 years ago

11

6n +5<7n + 10

1 answer:

RoseWind [281]2 years ago

8 0

Answer:

the answer is

Step-by-step explanation:

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Help!!!!!!!! I’m taking a test!

Licemer1 [7]

Answer:

They are alike because they are both functions and they both can be drawn with a single stroke of the pencil.

4 0

2 years ago

-9x - x - 7x² - 6x² + 8 +6<br><br><br><br> Help please

hammer [34]

Answer:

$\boxed{ \bold{ \huge{ { \sf{ - 13 {x}^{2} - 10x + 14}}}}}$

Step-by-step explanation:

$\sf{ - 9x - x - 7 {x}^{2} - 6 {x}^{2} + 8 + 6}$

Collect like terms

⇒ $\sf{ - 7 {x}^{2} - 6 {x}^{2} - 9x - x + 8 + 6}$

⇒ $\sf{ - 13 {x}^{2} - 10x + 8 + 6}$

Add the numbers

⇒ $\sf{ - 13 {x}^{2} - 10x + 14}$

Hope I helped!

Best regards!!

3 0

3 years ago

Read 2 more answers

a student studies the same amount of time each day for a test in 4 days she studied 60 minutes which equation shows this relatio

Keith_Richards [23]

Y=mx
m=amount of time per day studied
y=time
x=number of days
we have
60=m(4)
divide by 4
15=m

y=15x

8 0

2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

2 years ago

Suppose y varies directly as x, and y =15 when x = 3. Find the constant of variation (k).

vovangra [49]

Answer:

k = 5

Step-by-step explanation:

y = kx

15 = k(3)

k = 15/3

k = 5

8 0

2 years ago