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3 years ago

Why can we sometimes hear noises in the stomach during digestion ?

Chemistry

1 answer:

aleksandrvk [35]3 years ago

7 0

Because that's when your hungry or you feel something so the body needs food for energy

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The energy stored in molecular bonds is called _____.

makvit [3.9K]

Correct answer is chemical energy.

Reason:

For the chemical reactions to occur, energy is to be supplied for breaking and reorganization of bonds. This energy can be in form of heat, light, etc. Since, breaking of bonds results in chemical reactions to occur, t<span>he energy stored in molecular bonds is called Chemical energy.</span>

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4 years ago

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Which of the following solutions would have the lowest freezing point? 1.0 nacl 3.0 nacl 2.0 nacl or 5.0 nacl

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The solution that will have the lowest freezing point is 5.0 SODIUM CHLORIDE.
Adding solute to solvents usually result in the depression of the freezing point. The higher the quantity of the solute that is added, the lower the freezing point of the solution.

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4 years ago

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What evidence did you see of the microscope resolving power

SOVA2 [1]

I’m stupid I can’t even answer this

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3 years ago

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2C(s)+O2(g)2H2(g)+O2(g)H2O(l)→2CO(g)→2H2O(g)→H2O(g)ΔHΔHΔH=−222kJ=−484kJ=+44kJ Use the thermochemical data above to calculate the

sveticcg [70]

Answer : The change in enthalpy for the reaction is, 175 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The main reaction is:

$H_2O(l)+C(s)\rightarrow CO(g)+H_2(g)$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $2C(s)+O_2(g)\rightarrow 2CO(g)$ $\Delta H_1=-222kJ$

(2) $2H_2(g)+O_2(g)\rightarrow 2H_2O(g)$ $\Delta H_2=-484kJ$

(3) $H_2O(l)\rightarrow H_2O(g)$ $\Delta H_3=44kJ$

Now we are dividing reaction 1 by 2, dividing reverse reaction 2 by 2 and then adding all the equations, we get :

(1) $C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)$ $\Delta H_1=\frac{-222kJ}{2}=-111kJ$

(2) $H_2O(g)\rightarrow H_2(g)+\frac{1}{2}O_2(g)$ $\Delta H_2=\frac{484kJ}{2}=242kJ$

(3) $H_2O(l)\rightarrow H_2O(g)$ $\Delta H_3=44kJ$

The expression for change in enthalpy of the given reaction is:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(-111)+(242)+(44)$

$\Delta H=175kJ$

Therefore, the change in enthalpy for the reaction is, 175 kJ

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4 years ago

Which structures are haploid? select all that apply. which structures are haploid? select all that apply. gametophyte spores zyg

spayn [35]

<span>While looking at the life cycle of fern the structures that categorized under haploid are Egg, Spores, and Gametophyte. Spores are haploids that are in turn turned into haploid gametophytes through mitosis. The haploid gametophytes produce gametes and eggs also through mitosis which are haploid.</span>

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3 years ago