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2 years ago

7

A train travels from Ambervale to Westbrook at a constant speed of 96km/h. If the trip takes a total of 3 hours 20 minutes, what

is the distance between Amberville and Westbrook?

1 answer:

julia-pushkina [17]2 years ago

4 0

320km I think, I hope I’m right

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Why does the graph of a proportional relationship must pass through the origin (0,0)

ELEN [110]

Answer:

Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.

4 0

3 years ago

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0

2 years ago

irakobra [83]

A function can be represented by equations and tables

4 users are logged in by 9am
The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

$g(x) = \frac14 \sqrt{x - 3} + 3$

At 9am, x = 9.

So, we have:

$g(x) = \frac14 \sqrt{9 - 3} + 3$

$g(x) = \frac14 \sqrt{6} + 3$

Simplify

$g(9) = 3.6$

Approximate

$g(9) = 4$

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

$x - 3 = 0$

Solve for x

$x = 3$

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

$g(x) = \frac14 \sqrt{x - 3} + 3$

$g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3$

When x = 23, we have:

$g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4$

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0

2 years ago

35 POINTS PLEASE HELP

Lunna [17]

Answer:

The percentage error of measurement is 5.63 %

Step-by-step explanation:

Given as :

The measure length of the fence = 150 feet

The actual length of the fence = 142 feet

Let the percentage error in measurement = x

So, x = $\dfrac{\textrm measured value - \textrm actual value}{\textrm actual value}$ ×100

Or, x = $\dfrac{\textrm 150 - 142}{142}$ ×100

or, x = $\dfrac{\textrm 8}{142}$ ×100

or, x = 5.63 %

Hence The percentage error of measurement is 5.63 % Answer

4 0

2 years ago

Read 2 more answers

To help solve the trigonometric inequality 2sin^2(x)+. cos(2x)-2<-1, Tracey successfully graphed the equations y=2sin^2(x) +c

vichka [17]

Answer: B

Step-by-step explanation: I took the quiz and got it right

Also, if you graph the equations on a graphing calculator, the lines are right on top of each other, so the first equation can't be less than -1, so no solutions

3 0

2 years ago

Read 2 more answers