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madam [21]
3 years ago
11

Can someone please help???

Mathematics
2 answers:
Yanka [14]3 years ago
5 0

Answer:

[tex]x {y}^{3} \sqrt{25 {x}^{7} {y}^{4} } \\ \\ = {xy}^{3} \sqrt{ {5}^{2} {x}^{7} {y}^{4} } \\ \\ = {xy}^{3} \times \{ ({5}^{2} ) {}^{ \frac{1}{2} } ( {x}^{7} ) {}^{ \frac{1}{2} } ( {y}^{4} ) {}^{ \frac{1}{2} } \} \\ \\

emmasim [6.3K]3 years ago
4 0

Answer:

x {y}^{3}  \sqrt{25 {x}^{7} {y}^{4}  }  \\  \\  =  {xy}^{3}   \sqrt{ {5}^{2} {x}^{7}   {y}^{4} }  \\  \\  =  {xy}^{3}  \times  \{ ({5}^{2} ) {}^{ \frac{1}{2} } ( {x}^{7} ) {}^{ \frac{1}{2} } ( {y}^{4} ) {}^{ \frac{1}{2} }  \} \\  \\  =  {xy}^{3}  \times (5 \times  {x}^{ \frac{7}{2} }  \times  {y}^{2} ) \\  \\  = 5 \times  {x}^{(1 +  \frac{7}{2}) }  \times  {y}^{(3 + 2)}  \\  \\  = { \boxed{ \boxed{5   {y}^{5} \sqrt{ {x}^{9} }  }}}

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