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adell [148]
3 years ago
9

If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?

Mathematics
2 answers:
Dovator [93]3 years ago
5 0

Keywords

quadratic equation, discriminant, complex roots, real roots

we know that

The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form  ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}

where

The <u>discriminant</u> of the <u>quadratic equation</u>  is equal to

b^{2}-4ac

if  (b^{2}-4ac)> 0 ----> the <u>quadratic equation</u> has two <u>real roots</u>

if  (b^{2}-4ac)=0 ----> the <u>quadratic equation</u> has one <u>real root</u>

if  (b^{2}-4ac)< 0 ----> the <u>quadratic equation</u> has two <u>complex roots</u>

in this problem we have that

the <u>discriminant</u> is equal to -8

so

the <u>quadratic equation</u> has two <u>complex roots</u>

therefore

the answer is the option A

There are two complex roots

SVETLANKA909090 [29]3 years ago
3 0
Hello there, the correct answer is:

A.
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Please answer both with work,please use a paper and picture, thanks ​
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Answer:

a.  $ \frac{\textbf{17}}{\textbf{4}} $

b.  $ \frac{\textbf{3}}{\textbf{8}} $

Step-by-step explanation:

a. $ \textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}} $

A mixed fraction of the form $ a\frac{x}{y} = a + \frac{x}{y} $

$ \therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4} $

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$ = \frac{\textbf{17}}{\textbf{4}} $

b. $ \textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}} $

A mixed fraction of the form $ -c\frac{a}{b} = - c - \frac{a}{b} $

$ \therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8} $

$ = 1 - \frac{5}{8} $

$ = \frac{8 - 5}{8} $

$ = \frac{\textbf{3}}{\textbf{8}} $

Hence, the answer.

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Step-by-step explanation:

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FOIL

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