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Licemer1 [7]
2 years ago
8

Find the circumference and the area of a circle with radius 8 yd.

Mathematics
2 answers:
Bezzdna [24]2 years ago
8 0

Answer:

Area: 200.96yd²

Circumference: 50.24yd

Step-by-step explanation:

See attached image

Ivenika [448]2 years ago
3 0

Answer:

C = 50.24 yd

A = 200.96 yd²

Step-by-step explanation:

<u>Formulas:</u>

C=2\pi r

  • C = circumfrence
  • r = radius

A=\pi r^2

  • A = area
  • r = radius

<u>Calculations:</u>

C=2(3.14)(8)\\C=50.24

A=(3.14)(8)^2\\A=3.14(64)\\A=200.96

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nordsb [41]

Answer:

-9 =x

Step-by-step explanation:

We know these are similar triangles

We can use ratio's to solve

Let CS = y  and XR = y+y or 2y

y           x+19

------ = ------------

2y         x+29

We can simplify the ratio on the left by dividing by y

1           x+19

------ = ------------

2         x+29

Using cross products

1(x+29) = 2(x+19)

Distribute

x+29 = 2x+38

Subtract x from each side

x-x+29 = 2x-x+38

29 = x+38

Subtract 38 from each side

29-38= x+38-38

-9 =x

8 0
3 years ago
Reasoning Kareem cannot decide which of two washing machines to buy. The selling price of each is $720. The first is marked down
Marina CMI [18]

Answer:

store one

Step-by-step explanation:

Store One:

$720(0.50)=$360

$720-$360=$360

Store Two:

$720(0.30)=$216

$720-$216=$504

$504(0.20)=$100.8

$504-$100.8=$403.2

5 0
2 years ago
Does the table represent a function?(Only 2 hours to answer!)
alisha [4.7K]

Answer: (a) Yes. The table is a function.

<u>Step-by-step explanation:</u>

In order to be a function, there cannot be any duplicate x-values.

In the given table, each x-value is different so this IS a function.

6 0
3 years ago
Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

x^3=x\cdot x^2, and x(x^2+2x+1)=x^3+2x^2+x. Subtracting this from the numerator gives a remainder of

(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

8x^2=8\cdot x^2, and 8(x^2+2x+1)=8x^2+16x+8. Subtracting this from the previous remainder gives a new remainder of

(8x^2+12x+39)-(8x^2+16x+8)=-4x+31

-84x is not a multiple of x^2, so we're done. Then

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

4 0
3 years ago
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elena55 [62]

Answer:

8 months

Step-by-step explanation:

194-3m = 217-6m

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6 0
2 years ago
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