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Naily [24]
3 years ago
13

Write a function to represent each problem situation Carmen deposits $1000into simple interest account.The rate for the account

is 4%.Write a function the represent the balance in the account as a function of time t
Mathematics
1 answer:
kolezko [41]3 years ago
7 0

The function the represent the balance in the account as a function of time t is p(t) = 1000 + 40t

<h3><u>Solution:</u></h3>

Given that,

Carmen deposits $1000 into simple interest account

The rate for the account is 4%

To find: function the represent the balance in the account as a function of time t

Given is simple interest account

The formula for simple interest is given as:

S.I = \frac{ prt}{100}

Where, "p" is the principal and "r" is the rate of interest and "t" is the number of years

In simple interest,

total amount after "t" years = principal + simple interest

Here in this question, Carmen deposits $1000

p_0 = 1000

r = 4 \% = \frac{4}{100} = 0.04

Thus we can frame a function as:

total amount after "t" years = principal + simple interest

p(t) = p_0 + (p_0 \times r \times t )

p(t) = 1000 + (1000 \times 0.04)t\\\\p(t) = 1000 + 40t

Where, p(t) is the amount after "t" years and p_0 is the principal sum

Thus the function is obtained

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D. Putting the taller of a each pair for 1 plot makes it the experiment rigged in favor of the plot with taller seedlings

E. Same issue as D.

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3 years ago
Using the digits 1, 2, 3, 4, 5, 6, 7, and 9, make 4 two-digit prime numbers. What is the sum of those four prime numbers?
mr_godi [17]

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3 0
3 years ago
A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

Answer:

7.7 km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

6.6^{2} +3.9^{2} =c^{2} (Substitute a=6.6 and b=3.9 into the equation)

43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3)  means that line passes through A(3,-6) => ok

b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
   ****** this equation is not the line passing through A & B *****

c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
   y-2 = -4x+4, rearrange
   y-2 = -4(x-1)  
   which means that it passes through B(1,2), so ok

d. y-2=-4(x-1)
   this is the same as the previous equation, so it passes through B(1,2), 
   this equation is ok.

Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
8 0
2 years ago
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