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Stolb23 [73]
3 years ago
7

How to subtract fractionslike this

Mathematics
2 answers:
omeli [17]3 years ago
7 0
Your answe would be 1 9/13
Dimas [21]3 years ago
3 0
Your answer would be 19/13
You might be interested in
I WILL MARK AS BRAINLIEST! Find The Mean Median Mode and Range
IgorC [24]

Answer:

mean= 3.28

mode= 0 ,7

median= 3

range= 7

8 0
3 years ago
Read 2 more answers
A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:
Dima020 [189]

Answer:

Part A) y=\frac{3}{4}x-\frac{1}{4}  

Part B)  y=\frac{2}{7}x-\frac{5}{7}

Part C) y=\frac{2}{7}x+\frac{8}{7}

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the  median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

N(3, 2) and M(-1,-1)

substitute the values

m=\frac{-1-2}{-1-3}

m=\frac{-3}{-4}

m=\frac{3}{4}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{3}{4}

point\ N(3, 2)

substitute

y-2=\frac{3}{4}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{3}{4}x-\frac{9}{4}

y=\frac{3}{4}x-\frac{9}{4}+2

y=\frac{3}{4}x-\frac{1}{4}  

Part B) Find the equation of the  right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 4

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ M(-1,-1) ----> midpoint LP

substitute

y+1=\frac{2}{7}(x+1)

step 5

Convert to slope intercept form

Isolate the variable y

y+1=\frac{2}{7}x+\frac{2}{7}

y=\frac{2}{7}x+\frac{2}{7}-1

y=\frac{2}{7}x-\frac{5}{7}

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ N(3,2)

substitute

y-2=\frac{2}{7}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{2}{7}x-\frac{6}{7}

y=\frac{2}{7}x-\frac{6}{7}+2

y=\frac{2}{7}x+\frac{8}{7}

7 0
3 years ago
A large box contains 18 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?
Katarina [22]
You need to multiply 25 by 18 to find the total.

25 x 18 = 450.

There are 450 chocolate bars in the large box
5 0
3 years ago
Read 2 more answers
You are drawing a map. Two cities on the map are 7 inches apart. You know the actual distance between them is 1,750 miles. What
swat32

Answer:

  • 1 inch : 250 miles
  • 1/15,840,000

Step-by-step explanation:

Map scale factors are usually written a couple of different ways. One of them is the number of miles represented by 1 inch. Here, that is ...

  1750 mi/(7 in) = 250 mi/in

Written that way, the scale factor is 1 in : 250 miles.

__

The other way the scale factor can be written is as a unitless ratio. That ratio is ...

  \dfrac{1\,\text{in}}{250\,\text{mi}}\times\dfrac{1\,\text{mi}}{5280\,\text{ft}}\times\dfrac{1\,\text{ft}}{12\,\text{in}}=\dfrac{1}{250\cdot 5280\cdot 12}=\dfrac{1}{15,840,000}

The map scale factor is 1 in : 250 miles, or 1/15,840,000.

5 0
3 years ago
Read 2 more answers
List all the possible rational roots for the polynomial x^3+x^2 - 3x+12
OLEGan [10]

Answer: Heyaa! ~

Your Answers are... ±1,±2,±3,±4,±6,±12

Step-by-step explanation:

Find every combination of ± p/q, where <em>p</em> is a factor of the constant and

<em>q</em> is a factor of the leading coefficient.

Hopefully this helps you! ^^

- Matthew

6 0
1 year ago
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