(x^2)/a^2+(y^2)/b^2=1
a>b
a=6, a^2=36
foci=(a^2-b^2)^(1/2)
4=(36-b^2)^(1/2)
16=36-b^2
b^2=36-16
b^2=20
b=2(5)^(1/2) or (20)^(1/2)
1=(x^2/36)+(y^2/20)
I think picture one and picture two are the same question anyways, hope this helps :)
Imagine to have three segment: 1 is x, another is x+7 and the last is x-5. You know that their sum is 50, so you can write:
x+(x+7)+(x-5)=50
simplify:
3x+7-5=50
3x=48
x=16
16+7=23
16-5=11
So the thee sides are 11, 16 and 23.
Hope this helped.
Answer:
(11) 7 thousandths (12) 7 ones (13) 7 tenths
Step-by-step explanation:
I got the answer because ummm thats where i saw the sevens were hehe
