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Stolb23 [73]
3 years ago
7

How to subtract fractionslike this

Mathematics
2 answers:
omeli [17]3 years ago
7 0
Your answe would be 1 9/13
Dimas [21]3 years ago
3 0
Your answer would be 19/13
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LAST ONE!! (:
joja [24]
First you find how much the shape has dilated. To d ok that you divide the size of the size already given to you from the bigger shape from the same did if the smaller shape. So 58÷6=9.7. The shape grew by 9.7. To find x you use the similar side of the other shape again and multiy that size by 9.7. So 9.7×3=29.1

x=29.1
4 0
3 years ago
Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa
zimovet [89]

Answer:

x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

Step-by-step explanation:

We are given that a quadratic equation

x^2-x-1=0

We have to solve the equation by completing square and find the value of b.

(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0

(x-\frac{1}{2})^2-\frac{1}{4}-1=0

(x-\frac{1}{2})^2-\frac{1-4}{4}=0

(x-\frac{1}{2})-\frac{5}{4}=0

(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0

(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2

x-\frac{1}{2}=\frac{\sqrt5}{2} and x-\frac{1}{2}=-\frac{\sqrt5}{2}

x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}

And x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}

Therefore,x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

6 0
3 years ago
Drag each equation to show if it could be a correct first step to solving the equation 3 (x + 8) =42
Evgen [1.6K]

Answer:

x=-62/13

Step-by-step explanation:

13x+104=42

13x=42-104

13x=-62

8 0
3 years ago
Read 2 more answers
Name a dance step and name TWO muscles used during the dance step:
TiliK225 [7]
I don’t know if this would be considered a dance step but an aerial uses your quad because you have to push off your front leg and your hamstring because you have to drive your back leg
6 0
3 years ago
Mr. Clarke built a deck around the swimming pool and sandbox in his backyard. What is the area of the decking that surrounds the
ss7ja [257]

Answer:

1,174.8\ ft^{2}

Step-by-step explanation:

we know that

The area of the decking is equal to the area of the parallelogram minus the area of the pool minus the area of the sand box

Remember that

21\frac{1}{2}\ ft=21.5\ ft

so

A=(50)(35)-(20)(25)-(21.5)(7)/2\\A= 1,750-500-75.25\\A=1,174.8\ ft^{2}

4 0
3 years ago
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