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3 years ago

The value of x + y is negative, and X is a

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

5 0

Answer:

'y' must be at least one more than 'x'

Step-by-step explanation:

example: let 'x' equal 4

in order for '4 - y' to be less than zero (a negative value) then the value of 'y' must 5 or less

4 - 5 = -1

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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

4 years ago

Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu

Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4 $a^{4}$ - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u² - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = $\frac{1}{4}$

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

a² = $\frac{1}{4}$ ⇒ a = ± $\frac{1}{2}$

Solutions are a = ± 1 , a = ± $\frac{1}{2}$

7 0

3 years ago

One batch of trail mix can be made by mixing 3 cups of granola with 0.75 cup of raisins. Hamid needs to make a bigger batch of t

Alika [10]

Answer:

Im pretty sure its C

7 0

4 years ago

Please hurry find the measure of S

Andrews [41]

Answer:

m∠S = 29.5

Explanation:

S $\huge\boxed {\sf \triangle}$ R

In this triangle, QR = SQ, which means its an isosceles triangle, angle S and R is similar.

Thus solve:

m∠S = (180° - 121°)/2

m∠S = 29.5°

3 0

2 years ago

Read 2 more answers

Please help find the missing angle measures

masya89 [10]

Answer:

127

Step-by-step explanation:

(n-2)180

(5-2)180

=540 for total angle

540-90(3)-143

=127

7 0

3 years ago

Read 2 more answers