Ask question

Ask question

All categories

2 years ago

11

The value of x + y is negative, and X is a

1 answer:

yKpoI14uk [10]2 years ago

5 0

Answer:

'y' must be at least one more than 'x'

Step-by-step explanation:

example: let 'x' equal 4

in order for '4 - y' to be less than zero (a negative value) then the value of 'y' must 5 or less

4 - 5 = -1

You might be interested in

Um I’m kinda confused and I need some help

mel-nik [20]

Answer:

with what

Step-by-step explanation:

what do you need help with if there was photo we can't see it

8 0

2 years ago

Which expression is equivalent to cot t sec t?

Solnce55 [7]

Answer: $csc(t)$

Step-by-step explanation:

Alright, lets get started.

The given expression is given as :

$cot( t) \times sec (t)$

We know quotient identity as :

$cot(t)=\frac{cos(t)}{sin(t)}$

Similarly, we know reciprocal identity as :

$sec(t)=\frac{1}{cos(t)}$

lets plug the value of cot and sec in given expression

$\frac{cos(t)}{sin(t)} \times \frac{1}{cos(t)}$

cos will be cancelled, remaining will be

$\frac{1}{sin(t)}$

Using reciprocal identity again, that will equal to :

$csc(t)$ ................... Answer (A)

8 0

3 years ago

For what values of t on the interval [0, 21 ]is the instantaneous velocity positive (the projectile moves upward)?

OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below 0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0

3 years ago

Instructions: Given the following constraints, find the maximum and minimum values for z.

loris [4]

Answer:

$x+3y\leq 0$

$x-y\geq 0$

$1) x+3y=0$

$x-y=0$

$-----$

$4y=0$

$y=0$

$x=0$

$(0,0)$

$2)(x+3y=0)3$

$3x-7y=16$

$3x+9y=0$

$3x-7y=16\\------\\16y=-16$

$y=-1$

$(3,-1)$

$3)(x-y=0)3$

$3x-7y=16$

$3x-3y=16$

$3x-3y=0$

$3x-7y=16\\------\\4y=-16$

$y=-4$

$x=4$

$(4,-4)$

$Z=-x+5y$

$(0,0):z=0$

$(3,-1):z=-8$

$(4,-4):z=-24$

$Maximum \:Value\: of\: z:0$

$Minimum\: Value\: of\: z:-24$

<u>OAmalOHopeO</u>

8 0

3 years ago

Solve the inequality if you can help i would appreciate it <br><br> n-9 < 4

saveliy_v [14]

Answer:

n<4+9

n<13

Step-by-step explanation:

5 0

3 years ago