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2 years ago

A. Using geometry terms, identify what the side road would be called?

Mathematics

1 answer:

Fofino [41]2 years ago

5 0

The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8

<h3>How to identify angle theorems?</h3>

A) From the attached image, the side roads resemble 2 parallel lines cut by a transversal.

Now, if we consider the roads to be very fat lines, then it means that the main road is the transversal while the two side roads are parallel to each other.

B) Vertical angles are defined as angles that are opposite of each other The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8when two lines cross

The supplementary angles would be: 3 and 5; 4 and 6

C) If a fourth road is constructed, it will be perpendicular to the main road, or perpendicular to the two side roads, and it will form a right triangle.

Thus, the acute angles of the triangles will be complementary because their sum will be 90°

Read more about Angle Theorems at; brainly.com/question/24839702

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First we note that the partial derivatives vanish simultaneously at one point:

$\begin{cases}f_x=2x+y=0\\f_y=x+2y=0\end{cases}\implies(x,y)=(0,0)$

so there is one critical point within the region $D$ .

The Lagrangian is

$L(x,y,\lambda)=x^2+xy+y^2+\lambda(x^2+y^2-1)$

and has partial derivatives

$L_x=2x+y+2\lambda x$
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Set each partial derivative to 0 to find the possible critical points within the disk $D$ . Then we notice that

$yL_x=2xy+y^2+2\lambda xy=0$
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$\implies xL_y-yL_x=x^2-y^2=0$

Since $x^2+y^2=1$ , we have

$x^2-y^2=x^2+y^2-2y^2=0\implies1=2y^2\implies y^2=\dfrac12\implies y=\pm\dfrac1{\sqrt2}$

And since $x^2-y^2=0$ , or $x^2=y^2$ , we also have

$x=\pm\dfrac1{\sqrt2}$

So we have four possible additional critical points to consider:

$f(0,0)=0$
$f\left(-\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac32$
$f\left(-\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac12$
$f\left(\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac12$
$f\left(\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac32$

It should be clear enough which of these correspond to the absolute extrema of $f$ over $D$ .

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3 years ago

Jaden says that two triangles are congruent if their interior angles are congruent. Is Jaden correct, and why?

Bogdan [553]

Answer:

Step-by-step explanation:

No. Congruent triangles should also have corresponding congruent side lengths.

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2 years ago

The result of which expression will best estimate the actual product of (Negative four-fifths) (three-fifths) (Negative StartFra

sattari [20]

Answer:

The Answer Is B

Step-by-step explanation:

-4/5 = -1 (Rounded)

3/5 = 1/2 (Rounded)

-6/7 = -1 (Rounded)

5/6 = 1 (Rounded)

If your looking for the whole thing it would be:

(-1)[1/2](-1)(1) = x

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4 years ago

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4 years ago

there are 36 capenters in a crew. Ona certain day,29 were present .What percent showed up for work?[round to the nearest tenth

aliina [53]

Answer:

Step-by-step explanation:

We assume, that the number 36 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 36, so we can write it down as 100%=36.

4. We know, that x% equals 29 of the output value, so we can write it down as x%=29.

5. Now we have two simple equations:

1) 100%=36

2) x%=29

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=36/29

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 29 is what percent of 36

100%/x%=36/29

(100/x)*x=(36/29)*x - we multiply both sides of the equation by x

100=1.24137931034*x - we divide both sides of the equation by (1.24137931034) to get x

100/1.24137931034=x

80.5555555556=x

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now we have:

29 is 80.5555555556% of 36 to the nearest tenth is 81%

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3 years ago