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murzikaleks [220]
3 years ago
8

The perimeter of a rectangular lot is 198 ft. The width of the lot is 57 ft less than twice length. Find the

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Step-by-step explanation:

W = (2L -57)

P = 2×(L+W)

198 = 2× (L + 2L -57)

198 = 2× (3L - 57)

3L-57 = 198/2

3L-57 = 99

3L = 99+57

3L = 156

L = 156/3 = 52

W = 2(52) -57 = 104-57 = 47

so, the length = 52 ft

and the width = 47 ft

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