The perimeter of a rectangular lot is 198 ft. The width of the lot is 57 ft less than twice length. Find the
1 answer:
Step-by-step explanation:
W = (2L -57)
P = 2×(L+W)
198 = 2× (L + 2L -57)
198 = 2× (3L - 57)
3L-57 = 198/2
3L-57 = 99
3L = 99+57
3L = 156
L = 156/3 = 52
W = 2(52) -57 = 104-57 = 47
so, the length = 52 ft
and the width = 47 ft
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