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natka813 [3]
3 years ago
12

The sum of two numbers is 62, and their difference is 12. What are the numbers? Show work

Mathematics
2 answers:
Dimas [21]3 years ago
6 0
37 and 25 are the answers

Zanzabum3 years ago
4 0

Answer:

x = 37

y = 25

Step-by-step explanation:

Let the larger number = x

Let the smaller number = y

x + y = 62

<u>x - y = 12   </u>          Add

2x = 74               Divide by 2

x = 74/2

x = 37

x - y = 12

37 -y = 12          Subtract 37 from both sides

-y = 12 - 37

-y = -25            Multiply both sides by - 1

y = 25

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Use the given graph of f to estimate the intervals on which the derivative f ' is increasing or decreasing. (Enter your answers
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brainly.com/question/14330051

5 0
2 years ago
Which choice is equivalent to the expression below? 5√10+√40+√90 <br><br> the answer was 10√10
DaniilM [7]

Answer:

5\sqrt{10}+\sqrt{40} +\sqrt{90}=10\sqrt{10}

Step-by-step explanation:

We have the following expression:

5\sqrt{10}+\sqrt{40} +\sqrt{90}

Remember the property of root multiplication:

\sqrt[n]{x*y}=\sqrt[n]{x}\sqrt[n]{y}

Therefore:

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Also:

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Then we have that:

5\sqrt{10}+\sqrt{40} +\sqrt{90}=5\sqrt{10}+2\sqrt{10}+3\sqrt{10}

Remember the property of sum of roots:

a\sqrt{b}+2a\sqrt{b}=3a\sqrt{b}

Finally:

5\sqrt{10}+\sqrt{40} +\sqrt{90}=(5+2+3)\sqrt{10}

5\sqrt{10}+\sqrt{40} +\sqrt{90}=10\sqrt{10}

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