All categories

3 years ago

Students who prefer rock or classic rock to students who prefer all other types of music

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

8 0

16/26 ratio hope this helps

Nikolay [14]3 years ago

4 0

Since there is 12 students who prefer rock and 4 that prefer classic rock that will equal 16. add up all the other number to get 26 and your ratio will be: 16/26

You might be interested in

Enter the solution to the equation y=f(x) and y=g(x)

Crazy boy [7]

Answer:

trgfdsvcx

Step-by-step explanation:

kj,m

8 0

3 years ago

A model car is 3 3/4 inches long.using a scale of 1/2 inch=2 feet,find the actual length of the car

MaRussiya [10]

Answer:

14.25 because for every 1/2 inch, the car is 2 feet.

Step-by-step explanation:

8 0

3 years ago

The distance traveled (d) varies directly as the time (t) of

Helen [10]

Answer:

2.70 hours to travel 180 mi.

Step-by-step explanation:

The distance traveled (d) varies directly as the time (t) of travel, by the following formula:

$s = \frac{d}{t}$

In which s is the velocity.

It takes 63 min to travel 70 mi.

So i am going to find the velocity in miles per minute

$s = \frac{70}{63} = 1.11$

how many hours would it take to travel 180 mi?

I am first going to find the time in minutes, then divide by 60 to pass to hours.

$s = \frac{d}{t}$

$st = d$

$t = \frac{d}{s}$

$t = \frac{180}{1.11}$

$t = 162.16$

It takes 162.16 minutes = 162.16/60 = 2.70 hours to travel 180 mi.

6 0

2 years ago

The width of a rectangle is 7 inches less than its length. The area of the rectangle is 120 square inches. Solve for the dimensi

lukranit [14]

A) w + 7 = L
B) w * L = 120
A) w = L -7 then substituting this into B)
(L-7) * L = 120
L² -7L = 120
L² -7L -120 = 0
Solving by quadratic Formula:
L1 = 15
L2 = -8

If length = 15, then width = 8

4 0

3 years ago

Read 2 more answers

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

Natasha2012 [34]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the 9% confidence interval is given by:

$8.8104 \leq \mu \leq 11.1248$

We can calculate the mean with the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

And we can find the margin of error with:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this case is given by:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

And we can solve for the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for 95% confidence using the normal standard distribution is approximately 1.96 and replacing we got:

$SE = \frac{1.1572}{1.96}= 0.5904$

Now for the 98% confidence interval the significance is $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ the critical value would be 2.326 and then the confidence interval would be:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

8 0

3 years ago

Students who prefer rock or classic rock to students who prefer all other types of music​

Students who prefer rock or classic rock to students who prefer all other types of music