Answer:
Step-by-step explanation:
2g + h = 2 --------------(I)
g - h = -5------------(II)
g = -5 + h
Plugin g = -5 + h in equation (I)
2(-5 + h) + h = 2 {Distributive property:a(b+c) = a*b +a*c}
(-5)*2 + h *2 + h= 2
-10 + 2h + h = 2
3h = 2 + 10
3h = 12
h = 12/3
h = 4
Substitute h= 6 in equation (I)
2g + 4 = 2
2g = 2 - 4
2g = -2
g = -2/2
g = -1
bearing in mind that a <u>circle</u> means the round thing, so only the points on the round thing are ON the circle, others like the RC chord or the PQ diameter or the point C are NOT ON the circle.
Answer:
Step-by-step explanation:
|x-2|>5
x-2<-5
x<-3
or x-2>5
x>7
