$If\ it's\ a\ rhombus,\ then\ |\angle1|=26^o\\\\|\angle1|+|\angle2|+26^o=180^o\ \ /it's\ a\ triangle/\\\\26^o+|\angle2|+26^o=180^o\\52^o+|\angle2|=180^o\ \ \ |subtract\ 52^o\ from\ both\ sides\\\boxed{|\angle2|=128^o}$

7 0

2 years ago

Hey and I supposed to add or multiple when there is volume?

MrMuchimi

Answer:

mutiply

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!

Darina [25.2K]

CB = DA = √3*3+1*1 = √10
CD = BA = √2*2+1*1 = √5

Sum is 2√10 + 2√5 ≈ 10.8. So answer A.

4 0

2 years ago