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1 year ago

20% of a number is 17 . find the number

Mathematics

1 answer:

Nesterboy [21]1 year ago

3 0

Answer:

Step-by-step explanation:

20% of a number is 17 . find the number

divide 17 by 20 and you find 1%, multiply by 100 and you get 100%

x = 17 : 20 * 100

x = 0.85 * 100

x = 85

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Answer:

Step-by-step explanation:12-4=8

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2 years ago

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lesantik [10]

Write and solve an equation of ratios:

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-------------- = ------------
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3 years ago

The Royal Fruit Company produces two types of fruit drinks. The first type is 60% pure fruit juice, and the second type is 85% p

andrew11 [14]

Answer: There are 32 pints of first type and 128 pints of second type in mixture.

Step-by-step explanation:

Since we have given that

Percentage of pure fruit juice in first type = 60%

Percentage of pure fruit juice in second type = 85%

Percentage of pure fruit juice in mixture = 80%

We will use "Mixture and Allegation" to find the ratio of first and second type in mixture:

First type Second type

60% 85%

80%

------------------------------------------------------------------------

85-80 : 80-60

5% : 20%

1 : 4

so, the ratio of first and second type is 1:4.

Total number of pints of mixture = 160

Number of pints of mixture of first type in mixture is given by

$\dfrac{1}{5}\times 160\\\\=32\ pints$

Number of pints of mixture of second type in mixture is given by

$\dfrac{4}{5}\times 160\\\\=4\times 32\\\\=128\ pints$

Hence, there are 32 pints of first type and 128 pints of second type in mixture.

6 0

3 years ago

Select the example which illustrates the distributive property of 7 × 39

Lemur [1.5K]

Answer:

d) 7(30 + 9) = 7(30) + 7(9)

Step-by-step explanation:

Distributive method:

a(b + c) = ab + ac

Here given:

7 × 39

Among the option's:

1st option (7 + 3) (7 + 9) is wrong, changes final answer.

2nd option (7 × 30) + 9 is wrong, changes final answer.

3rd option 39 × 7 shows commutative property of multiplication.

4th option show distributive method.

3 0

9 months ago

Read 2 more answers

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

2 years ago