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jonny [76]
4 years ago
10

Which set of numbers does 4/7 belong to?

Mathematics
1 answer:
artcher [175]4 years ago
7 0

Option A: Real numbers

Option D: Rational number

Solution:

To find \frac{4}{7} is which type of number:

Option A: Real numbers

Real numbers include natural numbers, whole numbers, integers, rational numbers, irrational numbers.

Therefore, \frac{4}{7} is a real number.

Option B: Natural numbers

Number starting from 1 and goes on. i.e. 1, 2, 3, ....

There is no fractions and negative numbers in natural numbers.

So, \frac{4}{7} is not a natural number.

Option C: Irrational number

A irrational number is a number which cannot be written as ratio of two numbers.

So, \frac{4}{7} is not a irrational number.

Option D: Rational number

A rational number is a number that can be in the form \frac{p}{q}, where p and q are integers and q is not equal to zero.

So, \frac{4}{7} is a rational number.

Option E: Integers

Integers are like whole numbers but they also have negative numbers.

So, \frac{4}{7} is not integers

Option F: Whole numbers

Number starting from 0 and goes on.

There is no fractions and negative numbers in whole numbers.

So \frac{4}{7} is not a whole number.

Therefore Option A and Option D is the correct answer.

Hence \frac{4}{7} belongs to real numbers and rational numbers.

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Identify the DELETION mutation from the following DNA sequence:ATG CCA AAT
Umnica [9.8K]

Answer

Hello, There!

:Identify the DELETION mutation from the following DNA sequence

ATG CCA AAT.

Hope this helps!

4 0
3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
What is the solution to the following system?
notsponge [240]

Answer:

the answer is c (2,1,0)

Step-by-step explanation:

4 0
3 years ago
What is the answer to <br>3p-5&gt;2p+p-7
svet-max [94.6K]

Step-by-step explanation:

3p−5>2p+p−7

3p−5>3p−7

3p−5−3p>3p−7−3p

−5>−7

−5+5>−7+5

0>−2

Answer:

All real numbers are solutions.

-sammy

Hope this helps u mark me as brainiest if u think its right

3 0
3 years ago
Read 2 more answers
Solve the equation for x.<br><br><br> x2 = 576<br> /\<br> || <br> is supposed to be 2 over x
aleksklad [387]

Answer:

288

Step-by-step explanation:

2/x = 576

you have to make the x by itself so you would have to multiply 1/2 to 2/x for the first part

then you would carry the 1/2 over to 576 and multiply that by 1/2

the answer would become x = 288

5 0
3 years ago
Read 2 more answers
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