Answer:
Option (D)
Step-by-step explanation:
Surface area of a square pyramid is determined from the formula,
Surface area = Area of the square base + 4(Area of one lateral triangular side)
Area of the base = (Side)²
= 8²
= 64 cm²
Area of one lateral triangle = 
= 
= 32 cm²
Therefore, surface area of the square pyramid = 64 + 4(32)
= 64 + 128
= 192 cm²
Therefore, Option (D) will be the correct option.
We need to solve -3x+4y=12 for x
Let's start by adding -4y to both sides
-3x+4y-4y=12-4y
-3x=-4y+12
x = (-4y+12)/-3
x= 4/3 y -4
Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1
1/4 x -1/3 y =1
1/4 (4/3 y -4) -1/3 y =1
Use the distributive property
(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1
1/3 y -1 - 1/3 y =1
Now combine like terms
(1/3y -1/3y) + (-1) =1
= -1
-1 = 1
Now add 1 to both sides
0=2
So there are no Solutions
The answer is C
I hope that's help Will :)
Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
Judging by the question I noticed that the two both share x^3 in common. You can divide x^4 by x^3 and get x as a result, and x^3 can still divide into itself.
Thus your answer should be C, x^3
