What is 7 1/3 + 5 4/5

Mathematics

1 answer:

Alecsey [184]2 years ago

4 0

Answer:

1.5333333

Step-by-step explanation:

7 1/3 + 5 4/5 = 23/15 =1 8/15 =1.53

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When testing for current in a cable with eight color-coded wires, the author used a meter to test five wires at a time. How man

balu736 [363]

Answer:

56 different tests

Step-by-step explanation:

Given:

Number of wires available (n) = 8

Number of wires taken at a time for testing (r) = 5

In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.

So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

$^nC_r=\frac{n!}{r!(n-r)!}$

Plug in the given values and solve. This gives,

$^8C_5=\frac{8!}{5!(8-5)!}\\\\^8C_5=\frac{8\times 7\times 6\times 5!}{5!\times 3\times2\times1}\\\\^8C_5=56$

Therefore, 56 different tests are required for every possible pairing of five wires.

6 0

3 years ago

What is the probability of flipping a coin 10 times and getting tails 7 times ? Round your answer to the nearest tenth of a perc

KatRina [158]

Answer:

Option C: 11.7%

Step-by-step explanation:

The number of elements in sample space when a coin is flipped 10 times will be:

$n(S) = 2^{10} \\= 1024$

Let A be the event that the tails appear 7 times:

Then,

$C_{(n,k)}=\frac{n!}{(k!)(n-k)!} \\where\\n=population\\k=picks\\In our case, k =7\\and\\n=10\\C_{(10,7)}= \frac{10!}{(7!)(10-3)!}\\= 120\\So, \\P(A) = \frac{n(A)}{n(S)} \\P(A) = \frac{120}{1024} \\= 0.1171\\$