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aliya0001 [1]
4 years ago
7

Betty has 741 coins in her piggy bank, worth a total of 10,725 cents. The piggy bank only contains quarters and dimes. How many

dimes does Betty have?
Mathematics
1 answer:
quester [9]4 years ago
6 0
Let quarters = q and
Dimes = d

We have 741 coins total so q + d = 741

Since quarters are 25 cents and Dimes are 10 cents then

25q + 10d = 10725 cents

Now we have 2 equations that we can solve using addition or substitution.

Using addition, first multiply the first equation by -10

-10 (q+d) = 741 (-10)
-10q - 10d = -7410

Now add the equations together

(-10q -10d = -7410)
+ (25q + 10d =10725)
________________
15q = 3315
q = 3315 / 15
q = 221
this is the number of quarters

Now plug this back into the original equation

q + d = 741
221 + d = 741
d = 741 - 221
d = 520

There are 520 dimes

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Answer:

Part 1)

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Part 2)

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The solution is the point (3.8,1.2)

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Part 3)

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Step-by-step explanation:

Part 1) we have

-31x-19y=95 -----> equation A

-14x+19y=76 ---> equation B

Solve the system of equations by elimination

Adds equation A and equation B

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x=-3.8

Find the value of y

-14(-3.8)+19y=76

19y=76-53.2

y=22.8/19=1.2

The solution is the point (-3.8,1.2)

The system has only one solution

therefore

The system is consistent independent

Part 2) we have

31x-19y=95 -----> equation A

14x+19y=76 ---> equation B

Solve the system of equations by elimination

Adds equation A and equation B

31x+14x=95+76

45x=171

x=3.8

Find the value of y

14(3.8)+19y=76

19y=76-53.2

y=22.8/19=1.2

The solution is the point (3.8,1.2)

The system has only one solution

therefore

The system is consistent independent

Part 3) we have

31x+19y=95 -----> equation A

14x-19y=76 ---> equation B

Solve the system of equations by elimination

Adds equation A and equation B

31x+14x=95+76

45x=171

x=3.8

Find the value of y

14(3.8)-19y=76

-19y=76-53.2

y=-22.8/19=-1.2

The solution is the point (3.8,-1.2)

The system has only one solution

therefore

The system is consistent independent

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