Answer:

Step-by-step explanation:
For any angle
, we have that:

Quadrant:
means that
is in the first quadrant. This means that both the sine and the cosine have positive values.
Find the cosine:







Since the angle is in the first quadrant, the cosine is positive.

Answer:
-0.03
Step-by-step explanation:
-59x+3.2=5
-59x=5-3.2
-59x=1.8
x=1.8/-59
x=-0.03
35 - 14 = 21
3 * 6 = 18
3.5 * 6 = 21
Thus Juan is around the age of 3.5 and Lola is 31.5 I believe
Im not quite sure however I think this is the answer, I hope it helps ^-^
Answer:
first we need to substitute g(t) value in h(t) value and then evaluate the expression as follows :
h(g(t))=3(t-1)²+4(t-1).
by solving
h(g(t))=3(t²+1-2t)+4t-4
h(g(t))=3t²-2t-1 will.be the final answer
The factor of three is six factor of two is to 3 is three factor of two is 22 is four and poster of four is 22 Answer