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ale4655 [162]
3 years ago
11

En Vision Algebra 2

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Step-by-step explanation:

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Answer Please first = brainliest only if correct.
Kisachek [45]

Answer:

3x + 2y = 315 -----(1)

2x + 4y = 450 -----(2)

from (1) 3x + 2y = 315

2y = 315-3x

y = 157.5 - 3/2x ---- (3)

substitute (3) into (2)

2x + 4y = 450

2x + 4(157.5 - 3/2x ) = 450

2x + 630 - 6x = 450

-4x = -180

x = 45 ---- (4)

substitute (4) into (3)

y = 157.5 - 3/2x

y = 157.5 - 3/2(45)

y = 90

a haircut,x = 45 minutes

dye hair,y = 90 minutes

3 0
4 years ago
How many and what type of solutions does the equation have?
ella [17]

Answer: C

Step-by-step explanation:

Simplify to 4x^2 + 12x + 5 = 0 so that all the terms are on one side.

Do a part of the quadratic formula to see.

You only need to do the -b^2-4ac part. If it is negative, that means there are irrational solutions. If it is positive, it has two solutions. If it is 0, it has 1 solution.

12^2-4(4)(5) = 64

It is positive so it has two solutions.

7 0
3 years ago
The graph illustrates the process of changing ice at –50°C to steam at 150°C.
xenn [34]

Answer: 1, 3, both show a change in temp

8 0
3 years ago
The points (2, 3) and (6, 11) lie on a line. What is the slope of this line?
AveGali [126]

Answer:

8/4

Step-by-step explanation:

to do slope is y2 - y1 over x2 - x1, so it would be 11 - 3 for 8, then 6 - 2, leaving 8/4.

3 0
3 years ago
Let V be the vector space P3[x] of polynomials in x with degree less than 3 and W be the subspace
Pepsi [2]

By definition, the span of two vectors is the set of all possible linear combinations of said vectors. So, any element in W is obtaining by choosing two numbers a,b and building

a(7-8x-8x^2)+b(x^2-(5+6x)) = -8ax^2-8ax+7a+bx^2-6bx-5b

(a)

So, you can show a nonzero polynomial in W by choosing any values of a and b, as long as they're not both zero. To keep it as simple as possible, we can choose for example a=1, b=0 and we obtain one of the base vectors of W:

7-8x-8x^2

(b)

Factoring the powers of x, we see that a generic polynomial in W looks like

(b-8a)x^2-(8a+6b)x+7a-5b

So, we must build a polynomial

dx^2+ex+f

such that it is not possible that

\begin{cases}d=b-8a\\e=8a+6b\\f=7a-5b\end{cases}

For example, let's try the polynomial x^2+x+1

We should solve the system

\begin{cases}b-8a=1\\8a+6b=1\\7a-5b=1\end{cases}

And you can check that it has no solutions. So, the polynomial x^2+x+1 does not belong to W. On the other hand, it surely belongs to V, because it is a polynomial with degree less than 3. So, the polynomial x^2+x+1 belongs to V/W.

7 0
4 years ago
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