Answer:
![\dfrac{A}{x}+\dfrac{B}{x-6}](https://tex.z-dn.net/?f=%5Cdfrac%7BA%7D%7Bx%7D%2B%5Cdfrac%7BB%7D%7Bx-6%7D)
Step-by-step explanation:
Given the function
, to write the form of its partial fraction on decomposition, we will separate the two functions separated by an addition sign. The numerator of each function will be constants A and b and the denominator will be the individual factors of each function at the denominator. The partial fraction of the rational function is as shown below.
![= \dfrac{37}{x(x-6)}\\\\= \dfrac{A}{x}+\dfrac{B}{x-6}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B37%7D%7Bx%28x-6%29%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7BA%7D%7Bx%7D%2B%5Cdfrac%7BB%7D%7Bx-6%7D)
<em>Since we are not to solve for the constants, hence the partial fraction is </em>![\dfrac{A}{x}+\dfrac{B}{x-6}](https://tex.z-dn.net/?f=%5Cdfrac%7BA%7D%7Bx%7D%2B%5Cdfrac%7BB%7D%7Bx-6%7D)
1. We assume, that the number 92.4 is 100% - because it's the output value of the task.
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 92.4 is 100%, so we can write it down as 92.4=100%. </span>
<span>4. We know, that x is 150% of the output value, so we can write it down as x=150%. </span>
5. Now we have two simple equations:
1) 92.4=100%
2) x=150%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
92.4/x=100%/150%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 150% of 92.4
92.4/x=100/150
<span>(92.4/x)*x=(100/150)*x - </span>we multiply both sides of the equation by x
<span>92.4=0.666666666667*x - </span>we divide both sides of the equation by (0.666666666667) to get x
<span>92.4/0.666666666667=x </span>
<span>138.6=x </span>
x=138.6
<span>now we have: </span>
<span>150% of 92.4=138.6</span>
I believe b is about 16.3, hope this helps
Hello my Kings and Queens the answer would be 60 degrees because all angles of a triangle always add up to 180 degrees
The polynomial is not factorable with rational numbers