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Thepotemich [5.8K]
3 years ago
6

Find a ratio that is equivalent to 2:5.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

4:10 hope this helps

Step-by-step explanation:

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How do i find the volume of these similar solids? round to the nearest tenth HELP
FromTheMoon [43]

Answer:

The volume of the larger solid is 592.6\ mm^3

Step-by-step explanation:

<u><em>The question is</em></u>

If these solids are similar, find the volume of the larger solid

step 1      

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

z=\frac{x}{y}

we have

x=4\ mm\\y=3\ mm

substitute

z=\frac{4}{3} ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

z^3=\frac{x}{y}

we have

z=\frac{4}{3}

y=250\ mm^3

substitute the values

(\frac{4}{3})^3=\frac{x}{250}

solve for x

(\frac{64}{27})=\frac{x}{250}

x=250(\frac{64}{27})

x=592.6\ mm^3

4 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Use the dchnition of similarity to solve the following problem.
sveta [45]

Answer:

  1063 ft

Step-by-step explanation:

For shadow problems, we assume the sun's rays are parallel, so the triangles formed are similar. That means the ratio of height to shadow length is the same for each object.

  h/(580 ft) = (5.5 ft)/(3 ft)

  h = (5.5 ft)(580/3) ≈ 1063 ft

The height of the monument is about 1063 feet.

8 0
3 years ago
Order from least to greatest ! 1.36,1.3,1.63 and this other 0.42,3.74,3.47.
frosja888 [35]
If you are putting them all in order from least to greatest it would be 0.42, 1.3, 1.36, 1.63, 3.47,3.74. But, if you are separating them the first set of three numbers you wrote would be ordered 1.3, 1.36, 1.63. Then, the second set would be ordered 0.42, 3.47, 3.74. Hope this helped!!!
4 0
3 years ago
Read 2 more answers
If it takes a hoses to fill a tank in b minutes, how many hoses will it take to fill it in c
forsale [732]
In the terms it’s none of them because this is way to confusing
8 0
2 years ago
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