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Tanya [424]
3 years ago
9

The answer to an addition problem​

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
The answer is sum :)
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Pls answer fast and no bs links or I’ll report
Natalka [10]

Answer:

Step-by-step explanation:

a c e

5 0
3 years ago
Which of the following is the conjugate of the expression below when x> -3?
harina [27]

Answer:

7+\sqrt{x+3}

Step-by-step explanation:

The conjugate of a radical expression is obtained by changing the sign of the middle term.

The conjugate of a+\sqrt{b} is simply a-\sqrt{b}

Therefore, to obtain the conjugate of the given expression we simply shall be  changing the negative sign to positive;

The conjugate of 7-\sqrt{x+3} is simply;

7+\sqrt{x+3}

5 0
2 years ago
A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
Solve each equation you must use
n200080 [17]

1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

<u>Step-by-step explanation</u>:

The general form of quadratic equation is ax²+bx+c = 0

where

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

<u>To find the roots :</u>

  • Sum of the roots = b
  • Product of the roots = c

1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

  • Sum of the roots = -7+2 = -5
  • Product of the roots = -7\times2 = -14

The solution is given by (x-7) (x+2) = 0.

Therefore, the solutions are x=7 and x= -2.

2) The given quadratic equation is b² - 4b + 4 = 0.

From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

  • Sum of the roots = -2-2 = -4
  • Product of the roots = -2\times-2 = 4

The solution is given by (x-2) (x-2) = 0.

Therefore, the solution is x=2.

5 0
3 years ago
Can i have you SNAP CHATS <br> PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZz
tatiyna
Sureeeeeeeeeeeeeeeeeeeeee
4 0
2 years ago
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