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rjkz [21]
3 years ago
13

What is the equation​

Mathematics
2 answers:
slava [35]3 years ago
8 0

Answer:

B. (x+1)^2+(y-2)^2=9

Step-by-step explanation:

The given circle is centered at  (-1,2) and has radius 3 units.

The equation is given by

(x-a)^2+(y-b)^2=r^2

where (a,b) is the center and r is the radius.

We substitute the values to obtain;

(x--1)^2+(y-2)^2=3^2

(x+1)^2+(y-2)^2=9

alexandr1967 [171]3 years ago
4 0
The answer is the letter B.
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Hello,

Let's to remember,

To the perfect square:

X^2 +12x = -6

We would have to add 6^2

Because,

X^2 + 2.(6X) = -6

As (x+k) = x^2 +2xk +k

And,

2xk = 2.6x

xk = 6x

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Then,

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We would to add 36, and would stay:

X^2 + 6X = -6

x^2 +6x + 36 = -6 +36

X^2 +2.6x +6^2 = 30

(X+6)^2 = 30


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