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Fynjy0 [20]
3 years ago
14

Evaluate the expression 3x² + 2x - 4 for x =-2.

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

4

Step-by-step explanation:

3x² + 2x - 4

3(-2)² + 2(-2) - 4

3(4) - 4 - 4

12 - 4 - 4

12 - 8

= 4

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Which expression is equivalent to third- 32^3/5 ​
lara [203]

Answer:

Step-by-step explanation:

(-32)^3/5 =((-32)^1/5)^3 = (-2)^3 = -8. QED

6 0
3 years ago
Help a girl out!!! give brainliest!!
slavikrds [6]

Answer:

-1 i believe because that is the only x intercept. i apologize if this is wrong

Step-by-step explanation:

4 0
3 years ago
Given that R = 4 x + 8 y Find y when x = 4 and R = 32
victus00 [196]

R = 4 x + 8y [ Given ]

when ,

x = 4 and R = 32

★ Substituting the values

=> 32 = 4 × 4 + 8y

=> 32 = 16 + 8y

=> 8y = 32 - 16

=> 8y = 16

=> y = 8/16

=> y = 2

7 0
3 years ago
Read 2 more answers
PLEASE HELP WITH GEOMETRY WILL GIVE BRAINLIEST
sammy [17]

Answer:

Option D

Step-by-step explanation:

In the first three options we can evaluate the values of x with the help of Sine Rule for all the triangles

The Rule says

\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}

Where a , b and c are the sides opposite to the angles A, B and C of any ΔABC.

Hence , in order to determine unknown values of sides or angles , we need any 3 values from all 3 sides and 3 angles in a triangle. First Three options give us three values but the last option gives only 2.

Example

in first option we can apply Sine Rule as

\frac{\sin 84}{x}=\frac{\sin 63}{3}

\frac{0.994}{x}=\frac{0.891}{3}

x=\frac{0.991 \times 3}{0.891}

x=\frac{2.973}{0.891}

x=3.336

8 0
3 years ago
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
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