Answer:

Step-by-step explanation:
Given
Negative integer J
Required
Represent as an inequality of its inverse
The question didn't state if it's additive inverse or multiplicative inverse;
<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>
<em></em>
The inverse of -J is +J
To represent as an inequality (less than or equal), we have:

Solving further, it gives

(15x^3y^-8)÷(5x^2y^-4)
= 3xy^-4
(3x)/ y^4
The answer to your question is 10 seconds. I know this because:
distance divided by speed=time
let t=time
t=2*6(30/36)=10
t=10
So, it took Boris a total of 10 seconds to run up the out of service elevator.
Hope this helps!
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.

Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here