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goldenfox [79]
3 years ago
15

Find the midpoint of the segment with the given endpoints K(-2,-4) and L(-4,6)

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ K(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad L(\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-4-2}{2}~~,~~\cfrac{6-4}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~,~1)

ratelena [41]3 years ago
5 0

the answer is...... (-3,1)

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Step-by-step explanation:

X1 = 1

X2 = (X1) 2 - X1

X2 = 2 - 1

X2 = 1. implies that the second term of the sequence is 1.

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2 years ago
Joe’s annual income has been increasing each year by the same dollar amount the first year his income was 19,500. 8 years later
Anna007 [38]

Answer:

The question is either poorly constructed or it is a trick question. We do not know "In what year was his income 30,300" because the years correlating to his income are not disclosed.  Even assuming the question was meant to be posed as "how many years later was his income 30,300" it is still flawed.

Step-by-step explanation:

To arrive at Joe's annual income increase, first subtract 19,500 from 27,900 to get 8400, which is his overall increase over the 8 years. Now divide 8400 by 8. You will get 1050.  Beginning with his income of 27,900, add 1,050 to each successive income amount and you will get the following progression:

27,900, 28,950, 30,000, 31,050, 32,100, 33,150, 34,200, 35,250, 36,300.

Therefore, two years after his income was 27,900 it would be 30,000 and 6 years after that it would be 36,300.  It would  never be 30,300.

6 0
3 years ago
nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou
Olegator [25]

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

R = \dfrac{36}{50}

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468

Therefore, number of smiles Nathan expect to return is 468.

4 0
3 years ago
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Delicious77 [7]

Answer:

x = 51^o

Step-by-step explanation:

Given

Intersecting lines

Required

Find x

To do this, we make use of:

x + 23^o + 2x + 4^o = 180^o --- angle on a straight line

Collect like terms

x  + 2x = 180^o - 4^o - 23^o

3x = 153^o

Divide both sides by 3

x = 51^o

5 0
3 years ago
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Vinvika [58]

Answer:

x=6

Step-by-step explanation:

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7 0
2 years ago
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