Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A
A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11
B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29
Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18
Answer:
16
Step-by-step explanation:
1. Y= 5/4x -1.4
2.Y=-2/4x -7
Formula is Y=MX+B
To solve these equations you have to make the Y separate so add or subtract the x value depending on the charge remember what you do to one side you do to the other after you divide everything by the number in the Y value and for the x you put the y value on-top and make it a fraction
Answer:
I think the density is 4cm.
Hope that helps you.
Step-by-step explanation:
