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Dovator [93]
3 years ago
15

What is (6x100) + (1x10) + (7x1) + (9 x 1/10) + (2x 1/1000) in standard form?

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

617.902

Step-by-step explanation:

hope this helps :)

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What is the difference of 87.09 - 29.1
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2g + h =2<br>g -h= -5<br><br>find g and h step by step explanation​
wel

Answer:

Step-by-step explanation:

2g + h = 2 --------------(I)

g - h = -5------------(II)

   g = -5 + h

Plugin g = -5 + h in equation (I)

  2(-5 + h) + h = 2              {Distributive property:a(b+c) = a*b +a*c}

(-5)*2 + h *2 + h= 2

-10 + 2h  + h    = 2

             3h = 2 + 10

       3h = 12

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h = 4

Substitute h= 6 in equation (I)  

2g + 4 = 2

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    2g = -2

      g = -2/2

g = -1

6 0
2 years ago
How do you do this problem? See attached image
never [62]
Divide both sides by -6.
5 0
3 years ago
Read 2 more answers
Prove the theorem (AB )^T= B^T. A^T
Lisa [10]

Answer:

(AB)^T = B^T.A^T  (Proved)

Step-by-step explanation:

Given  (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\                = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T}  \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)

3 0
3 years ago
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