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4 years ago

How to I determine the domain of f(x) = ln(x+4)/e^x-2

Mathematics

1 answer:

denis23 [38]4 years ago

3 0

X>-4 and x not equal ln2

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You’re installing a new shower wall with square tiles that are one foot by one foot. The wall in your shower is a total of 7 fee

azamat

Answer:

A - It should be $2380.

Step-by-step explanation:

7 x 10 = 70 tiles needed total

70 x 34 = 2380

3 0

4 years ago

A pattern has 6 triangles to every 18 yellow triangles what is the ratio yellow triangles to blue triangles

polet [3.4K]

The ratio would be 3:1

( the 6 triangles are blue, which I’m pretty sure they are.)

Since there are 18 yellows and 6 blues, and the question calls for the ratio of the yellows to the blues, the ratio is 18:6. But you always have to simplify. The GCF is 6, so you would divide both of them by 6. The ratio is then 3:1.

7 0

3 years ago

Can someone who knows geometry help me

Anuta_ua [19.1K]

3) . Ddraw the radius to the right side of the chord. So you formed a right triangleNow let's apply Pythagoras

3.6² + 5.5²= x² ==> x = 6.57 ≈ 6.6

4) same logic but the other leg = x/2 you will find
x² = 133/4 & x =5.766≈ 5.8

5) arc ab = arc de (1st proposition)

7 0

3 years ago

Use a bar model to illustrate the equation 20-x =6. Explain how to you wold solve the equation

gayaneshka [121]

20-x=6
we just have to find x
so,
we will do like this
-x = 6-20
-x = -14
x = 14 is the write answer

3 0

3 years ago

Use Cramer's Rule to solve (if possible) the system of linear equations. (If not possible, enter IMPOSSIBLE.) 4x − 2y + 3z = −9

max2010maxim [7]

Answer:

The answer is:

$x=4.89\\y= -0.609\\z=-2.804$

Step-by-step explanation:

Before we start, we must be sure that the equations are written as follow:

$ax+by+cz =d$

As we have it in this particular case.

The first requirement to use Cramer's Rule is to have the equations as: ax+by-cz=d.

We start by calculating what it's called the determinant of the system. Represent by the letter D. This determinant is formed by the coefficients on the three equations of the system.

$4x -2y + 3z =-9 (eq.1)\\2x +2y +5z=-1 (eq.2)\\8x-5y-2z=15(eq.3)\\$

unknow quantities: x, y, z

x y z

D= $\left[\begin{array}{ccc}4&-2&3\\2&2&5\\8&-5&-2\end{array}\right]$

For solve this determinant of 3x3 we use the Rule of Sarrus. This rule consist in repeating line 1 and 2 under the line 3.

$D= \left[\begin{array}{ccccc}4&-2&3\\2&2&5\\8&-5&-2\\4&-2&3\\2&2&5\end{array}\right]$

Then we multiply the main diagonals and then we add them.

$(4*2*-2)= -16\\(2*-5*3)= -30\\(8*-2*5)= -80\\\\-16-30-80=-126$

After that we multiply the secondary diagonals and we subtract that value from the result of adding the multiplication of main diagonals.

$3*2*8=48\\5*-5*4=-100\\-2*-2*2=8\\\\48 -100 + 8= -44$

$D= \left[\begin{array}{ccccc}4&-2&3\\2&2&5\\8&-5&-2\\4&-2&3\\2&2&5\end{array}\right]= -126 - (-44) = -82$

So the system's determinant is

$D= -82$

We continue now with the x's determinant.

In the original x column we substitute the independent values, those are after the equal.

$Dx=\left[\begin{array}{ccc}-9&-2&3\\-1&2&5\\15&-5&-2\end{array}\right]$

Then we repeat the use of Sarru's Rule. Which is repeating line 1 and 2 under the line 3. After that we multiply the main diagonals and add the result. Then we multiply the the secondary diagonals and we subtract that value from the result of adding the multiplication of main diagonals.

$Dx= \left[\begin{array}{ccccc}-9&-2&3\\-1&2&5\\15&-5&-2\\-9&-2&3\\-1&2&5\end{array}\right]$

2) Multiplication of main diagonals

$(-9*2*-2) = 36 \\\\(-1*-5*3)= 15\\\\(15*-2*5)= -150\\\\36+15-150= -99$

3) Multiplicational of secondary diagonals

$(3*2*15)=90\\(5*-5*-9)= 225\\(-2*-2*-1)= -4\\90+225-4=311$

$Dx=-90- (311)= -401$

So the x's determinant is

$Dx= -401$

We continue now with the determinant of y and z columns. Following the previous 4 steps. In the original y and z column we substitute the independent values, those are after the equal.

$Dy =\left[\begin{array}{ccc}4&-9&3\\2&-1&5\\8&15&-2\end{array}\right]$ $Dz =\left[\begin{array}{ccc}4&-2&-9\\2&-2&-1\\8&-5&15\end{array}\right]$

$Dy =\left[\begin{array}{ccccc}4&-9&3\\2&-1&5\\8&15&-2\\4&-9&3\\2&-1&5\end{array}\right]$ $Dz =\left[\begin{array}{ccc}4&-2&-9\\2&-2&-1\\8&-5&15\\4&-2&-9\\2&-2&-1\end{array}\right]$