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3 years ago

Helpppp for those who can read bahasa pleaseee

Mathematics

1 answer:

wlad13 [49]3 years ago

7 0

Answer:

Step-by-step explanation:

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212.809 to round to the nearest whole number

Elodia [21]

Answer:

213

I hope this helps!

8 0

3 years ago

Assume that price is an integer variable whose value is the price (in US currency) in cents of an item. Assuming the item is pai

cestrela7 [59]

Answer:

$Change = (Paid*100) - Price$

Step-by-step explanation:

First of all we need to know the relation between 1 dollar and 1 cent in order to express everything in the units required in the question.

We know that $1 dollar = 100 cents$ , so the amount paid for the item with single dollars has to be multiplied by 100 to express its value in cents.

$Paid_{cents}=Paid_{dollars}*100$

Now that we have everything in cents, we can make the subtraction:

$Change_{cents} = Paid_{cents} -Price_{cents}$

Replacing the value in cents we get:

$Change = (Paid*100) - Price$

4 0

3 years ago

Drag each length to match it to an equivalent length. 2 yards 5 inches returned to choices list. 2 feet 8 inches4 yards9 feet2 y

Grace [21]

Answer:

2 yards 5 inches will be equivalent to 77 inches

Step-by-step explanation:

Given length -

2 yards 5 inches

One yard has 36 inches

Two yards will have 2*36 = 72 inches

Thus, 2 yards 5 inches will sum up to 72 inches + 5 inches = 77 inches

Hence, 2 yards 5 inches will be equivalent to 77 inches

6 0

3 years ago

Which of the following expressions is modeled on the number line?

Anton [14]

Answer is D. last one
2 * 3 = 6
On the number line, 0 to 3, it's 3 units
then 3 to 6, there's another 3 units
so 2 x 3(units) = 6

7 0

2 years ago

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago