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Temka [501]
3 years ago
10

A) b³(cm)³

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

puedes decirme l indicación para poder resolverlo

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Please answer with proof/work I give points
Phoenix [80]

Answer:

H. 8.874 hours

Step-by-step explanation:

There is a seven, that has the value of 7/100. 7/100 as a decimal is .07 because there is a 7 in the hundredths place. There has to be a number that contains 7/100, or a value in the hundredths place, and that is 8.874.

Hope this helps!

3 0
3 years ago
Read 2 more answers
What is the base five representation of The number 219
ICE Princess25 [194]

assuming 219_{10}

Then the column values for base five here are

5³  5²  5^{1}  5^{0}

We can get 1 × 5³ = 125 → 219 - 125 = 94

We can get 3 × 5² = 75 → 94 - 75 = 19

We can get 3 x 5^{1} → 19 - 15 = 4

and 4 = 4 × 5^{0}

Thus 219_{10} = 1334_{5}

As a check

(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219


3 0
3 years ago
100000000000000000000000000000000000000000+53624785326348756348927563482564328965342875634289573264
Arlecino [84]

Answer:

5.3624785e+55

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLeAsE sEnD hElP !!!!!!!!!!!!!!!!
Luba_88 [7]

Answer:

5 units

Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units

This gives us that

AG = BG = 5 units

3 0
3 years ago
Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two
Damm [24]

Answer:

7

Step-by-step explanation:

Let S be the set of all graphs having vertex set  \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

8 0
3 years ago
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