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zubka84 [21]
2 years ago
5

Is the ordered pair (6,5) a solution to the equation 3x - 4y = -2? Explain.

Mathematics
1 answer:
Citrus2011 [14]2 years ago
5 0
X=4y/3 - 2/3 is the awnser
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Each big square below represents one whole.
tatyana61 [14]

Answer:

45 percent /100 percent

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3 years ago
Solve. –4t ≤ 48 A. t ≥ –12 B. t ≤ –12 C. t ≥ 12 D. t ≤ 12
Oksana_A [137]
-4t \leq 48 \ \ \ : |(-4) \\  \\ t  \geq 12

<em>\\\ Ben</em>
3 0
3 years ago
Write (8 x 10) + (6 x 1) +(2 x 0.1) + (7 x 0.001) with words.
aleksklad [387]

Answer:

Eight times ten plus six times one plus two times one-tenth plus seven times one-thousandth.

Step-by-step explanation:

(8 x 10) = eight times ten

(6 x 1) = six times one

(2 x 0.1) = two times one-tenth

(7 x 0.001) = seven times one-thousandth

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4 0
2 years ago
-6x-14y=-20<br> -3x-7y=-10
Alex Ar [27]
ANSWER:

x = 10 / 3

y = 0

STEP-BY-STEP EXPLANATION:

We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.

Equation No. 1 -

- 6x - 14y = - 20

Equation No. 2 -

- 3x - 7y = - 10

First, we will make ( x ) the subject in the first equation and simplify accordingly.

Equation No. 1 -

- 6x - 14y = - 20

- 6x = - 20 + 14y

x = ( - 20 + 14y ) / - 6

x = ( - 10 + 7y ) / - 3

From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.

Equation No. 2 -

- 3x - 7y = - 10

- 7y = - 10 + 3x

- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]

- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]

- 7y = - 10 + ( 10 - 7y )

- 7y = - 7y

- 7y + 7y = 0

0y = 0

y = 0

Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.

x = ( - 10 + 7y ) / - 3

x = [ - 10 + 7 ( 0 ) ] / - 3

x = [ - 10 + 0 ] / - 3

x = - 10 / - 3

x = 10 / 3
6 0
3 years ago
5. REINFORCE Construct a 4th-degree polynomial with the following characteristics:
Eva8 [605]
A


- Harvard university professor
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