A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
It does not show variation
Step-by-step explanation:
Given
Required
Determine if there's direct variation between x and y
The general form of direct variation is:
Make y the subject of formula in the given parameters;
Compare to
<em>Since they are not of the same form, then the given equation do not show direct variation</em>
V = r² π h + 1/2 · 4/3 r³ π
V = 6² · 22/7 · 198 + 4/6 · 6³ · 22/7
V = 36 · 22 · 24 + 144 · 22/7 = 19,008 + 452.57 = 19,460.57 ≈ 19,461 ft³
Answer: B ) 19,461 ft³
