Emily has a bag of 20 fruit flavour sweets. 7 of the sweets are strawberry flavour, and 11 are lime flavour.

What is the solution to the system of equations graphed below? y = x + 2 y = 3x – 2 A. (0, 2) B. (2, 4) C. (4, 2) D. (0, –2)

love history [14]

Answer:

B. (2, 4)

Explanation:

<u>Given equations</u>:

a) y = x + 2

b) y = 3x – 2

Solve them simultaneously:

x + 2 = 3x – 2

x - 3x = -2 - 2

-2x = -4

x = 2

Then find y = x + 2 = 2 + 2 = 4

Solution: (x, y) = (2, 4)

3 0

2 years ago

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Which of the following is the equation of a line in slope-intercept form for a

Arada [10]

The slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

In this case the slope is...

1

The y-intercept is...

(0, -4)

Plug these numbers in for m and b respectively:

y = 1x + (-4)

y = x - 4

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

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Write the equation of the line in fully simplified slope-intercept form.

just olya [345]

Answer:

y= -7x-8

Step-by-step explanation:

The slope intercept form is y = mx + b.

First, find the slope. Use rise/run which gives you -7. <= negative bc its a negative slope.

Next, find the y intercept for b. It is -8.

Now, combine the numbers. y = -7x-8.

6 0

3 years ago

(-30(-7))-(210(-3))=

Vlad [161]

Answer:

840

Step-by-step explanation:

(−30)(−7) − (210)(−3)

=210 − (210)(−3)

=210 − (−630)

=840

Hope this helps!

brainliest?

:)

3 0

3 years ago

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago