The sentence has 22 letters. There are 13 consonants.
13/22 x 100% ≈ 59,1% chance that you pick a consonant.
Assuming that is it a family of four. They each would have a meal costing $10.50
Answer:
300
Step-by-step explanation:
Let x represent the number of adults in the zoo at 12 pm. Then the number of children at that time is 855 -x.
The number of remaining children is 1/5 of the number at 12 pm, so is ...
(855 -x)/5
The number of remaining adults is 1/4 of the number at 12 pm, so is ...
x/4
There are 36 more remaining children, so we have ...
(855 -x)/5 -x/4 = 36
171 -9x/20 = 36 . . . . . collect terms
135 = 9x/20 . . . . . . . . add (9/20)x-36
(20/9)(135) = x = 300 . . . . . multiply by 20/9
There were 300 adults in the zoo at 12 pm.
The sum of two consecutive odd integers is at most 123. find the pair with the greatest sum
two consecutive odd integers
2x+1,2x+3
The sum of two consecutive odd integers is at most 123
2x+1+2x+3≤123
Solve for x
2x+1+2x+3≤123
4x+4≤123
4x+4-4≤123-4
4x≤119
4/4x≤119/4
x≤119/4
x≤29.25
Substitute any numbers into x that are equal to 29 or less that are consecutive odd integers.
2x+1,2x+3
2 (29)+1,2 (29)+3
58+1,58+3
59,61
Check: 59+61=120
The pair of consecutive odd integers that have a sum of at most 123 are 59 and 61.