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3 years ago

Solve the equation using the Properties of Equality. 6a + 9 = 27 a =

Mathematics

1 answer:

Elis [28]3 years ago

3 0

A=3 because 6 times 3 is 18 and 18 plus 9 is 27

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masya89 [10]

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3 years ago

I need to simplify this question to simplest form. 49/100

NemiM [27]

Answer:

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Step-by-step explanation:

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3 years ago

A triangle has a hypotenuse of length 25 and one leg of length 24. What is the tangent of the larger acute angle of the triangle

cestrela7 [59]

Answer:

$\sin( \theta) = \frac{24}{25} \\ \theta = { \sin }^{ - 1} ( \frac{24}{25} ) \\ \theta = 73.7 \degree \\ \\ \tan( \theta) = \tan(73.7 \degree) \\ = 3.4$

8 0

3 years ago

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What is the center and radius?<br><br> X^2+y^2+6x-6y=-14

Zolol [24]

Answer:

Therefore,

$Center\ is\ C(-3,3)\\and\\Radius= 2\ units$

Step-by-step explanation:

Given:

A Equation of a Circle that is

$x^{2} +y^{2}+ 6x-6y=-14$

Which can be written as

$x^{2} +y^{2}+ 6x-6y+14=0$

To Find:

Center C( -g , -f ) = ?

radius = r =?

Solution:

General Equation of a Circle is given as

$x^{2} +y^{2}+ 2gx+2fy+c=0$

On Comparing the Given equation with the General equation we get the following values,

$2g=6\ and\ 2f=-6\ and\ c=14\\\therefore g=\frac{6}{2}=3\\ \\\therefore f=\frac{-6}{2}=-3\\$

Now, Center and Radius for above circle is given as

$C(-g,-f)=(-3,-(-3))=(-3,3)\\and\\radius = r=\sqrt{(g^{2}+f^{2}-c )} = \sqrt{(3^{2}+(-3)^{2}-14)}\\\\\therefore radius = r=\sqrt{(18-14)} \\\\\therefore radius = r=\sqrt{4}=2\ unit\\$

Therefore,

$Center\ is\ C(-3,3)\\and\\Radius= 2\ units$

6 0

4 years ago

Step by step explanation please

Oksanka [162]

Step-by-step explanation:

of what where is the question

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3 years ago

Read 2 more answers