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guapka [62]
2 years ago
8

Which of the following statements is false?

Mathematics
2 answers:
NARA [144]2 years ago
6 0

Answer:

I would say c, all whole numbers are rational

Step-by-step explanation:

Whole numbers can include all the natural numbers along with zero. It starts can from 0, 1, 2, 3, 4, 5, etc. But all whole numbers can not be natural numbers

Vsevolod [243]2 years ago
4 0

<u>Answer:</u>

C. All whole numbers are natural

<u>Step-by-step explanation:</u>

Natural numbers are those that are used for counting, and therefore include 1, 2, 3, 4... and so on, but they do not include 0.

Whole numbers are all numbers without a fractional part, and therefore include 0.

This is why not all whole numbers are natural numbers.

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Need help w this question thanksss!
elena55 [62]

Given:

A figure of a circle.

To find:

The value of x.

Solution:

Central angle theorem: According to this theorem, the central angle on an arc is twice of the subtended angle on that arc.

Using the central angle theorem, we get

x=2\times 35^\circ

x=70^\circ

Therefore, the value of x is 70 degrees.

4 0
3 years ago
You are at a sandwich shop. You can choose from white or rye bread,
ryzh [129]

Answer:

C.

Step-by-step explanation:

the subset consists of all the sandwiches with turkey and american cheese

6 0
4 years ago
System of equations y &gt;4, and y&gt; |x-1|
Paul [167]
Y>(+)x+1
Y>4

Y>(+)x
Y>3

X=3
6 0
3 years ago
Write an algebraic expression for the word expression.
max2010maxim [7]
1.  x+9
2. (b-5)+6
3. 15+5v
4. 2/3k
6 0
3 years ago
Read 2 more answers
Solve the following quadratic equation by completing the square: x² + 12x = 15
Lerok [7]
Answer:

x = -1.14 or -13.14

Explanations:

The given equation is:

x^2+12x\text{  =  15}

Find the half of 12, and add the square to both sides of the equation.

That is add 6² to both sides

x^2+12x\text{ + 6}^{2}\text{  =  15 + 6}^{2}\begin{gathered} (x+6)^2\text{ =  15  +  3}6 \\ (x+6)^2\text{ = 51} \\  \end{gathered}

Find the square root of both sides:

\begin{gathered} \sqrt[]{(x+6)^2_{}}=\pm\sqrt[]{51} \\ \text{x  +  6  = }\pm\sqrt[]{51} \\ x\text{  =  -6  }\pm\sqrt[]{51} \\ \text{x  = }-6\pm7.14 \\ x\text{  = -6+7.14  = }1.14 \\ x\text{ = -6 - 7.14} \\ \text{x = -13.14} \end{gathered}

x = -1.14 or -13.14

3 0
1 year ago
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