The area of the circular flower bed
=(13÷2)^(2 × pie
≈132.73 sq.feet
the amount of fertilizer needed
132.73÷10
=13.273
Thus 14 bags of fertilizer will be needed
hope it helps
Mohamed decided to track the number of leaves on the tree in his backyard each year. the first year, there were 500 leaves. each year thereafter, the number of leaves was 40% more than the year before. let f(n) be the number of leaves on the tree in Mohamed's backyard in the n^th year since he started tracking it. f is a sequence. what kind of sequence is it?
Number of leaves on the tree in first year = 500
The number of leaves was 40% more than the year before.
So rate of increase is 40/100 = 0.4
We use exponential growth formula,
f(n) = a(1+r)^n
Where a is the initial number, r is the rate of growth, n is the number of years
We know a= 500, r= 0.4
f(n) = 500(1+0.4)^n
f(n) = 500(1.4)^n
Plug in n=1,2,3...
f(1) = 500
f(2) = 500 * 1.4^1
f(3) = 500 * 1.4^2 and so on
From this we can see that the common ratio is 1.4
Hence it is a Geometric sequence.
Answer:
14
Step-by-step explanation:
Omar can make 14 whole dumplings. You change 2 3/4 cups to an improper fraction ( multiply the denominator and add the numerator ) and you get 11/4. Since you need 3/16 cups for one dumpling you have to find the greatest common denominator which is 16. You multiply 4 by 11 to get the numerator and end up with 44/16. Since you need 3/16 for one whole dumping you divide 44 by 3 and get 14.6 repeating. You cannot have a fraction of a dumpling so you round down and get the answer 14.
Answer:
36
Step-by-step explanation:
"Two more" = + 2
"quotient of a number and 6" = n/6
"equal to 8" = = 8
Set the equation:
n/6 + 2 = 8
Isolate the variable n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 2 from both sides.
n/6 + 2 (-2) = 8 (-2)
n/6 = 8 - 2
n/6 = 6
Isolate the variable n. Multiply 6 to both sides.
(n/6)(6) = (6)(6)
n = 6 * 6
n = 36
36 is your answer.
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The real solutions of f(x) = 0 is; x = -8, 0 and 4
<h3>How to find the roots of a polynomial graph?</h3>
When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.
Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.
From the given graph, the real solutions are at x = -8, 0 and 4
Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4
Read more about Polynomial roots graph at; brainly.com/question/14625910
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